Question

a triangle ABC is drawn to circumscribe a cicle and AD equals to 6 cm DB equals to 4 cm and CF equals to 3 cm then find the perimeter of ABC​

Answer 1

Answer:

In △ABC AB=AC

⇒∠B=∠C (Angles opposite to equal sides are equal)

Now using angle sum property

∠A+∠B+∠C=180

∘

⇒80

∘

+∠C+∠C=180

∘

⇒2∠C=180

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−80

∘

⇒∠C=

2

100

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=50

∘

now ∠C+∠x=180

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(Angles made on straight line (AC) are supplementary)

⇒50

∘

+∠x=180

∘

⇒∠x=180

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−50

∘

=130

∘

Answer 2

A triangle is drawn to circumscribe a circle and AD= 6cm, DB=4 cm, CF=3cm. The perimeter of triangle abc is 26 cm. Step wise explanation is given below:

- It is given that the

AD=6cm

BD=4cm

CF=3cm

- As we know that the tangents drawn from external point to a circle are equal.

- So,AD=AF=6cm

BD=BE=4cm

CF=CE=3cm

- By using these values

AB=AD+BD=6+4=10

BC=BE+CE=4+3=7

AC=AF+CF=6+3=9

- By using the foumula of perimeter

P=AB+BC+AC

P=10+7+9

P=26cm