A triangle ABC is drawn to circumscribe a circle if AB=6cm,BC=8cm and angle ABC = 90° , find radius of the circle.
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By Pythagoras theorem;
BC²=AB²+AC²
BC²= 8²+6²
BC² = 64+36
BC² = 100
BC = √100=10cm
Therefore diameter is also 10cm;
radius = Diameter /2
= 5 cm.
Hence found .
Thank you !
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BC²=AB²+AC²
BC²= 8²+6²
BC² = 64+36
BC² = 100
BC = √100=10cm
Therefore diameter is also 10cm;
radius = Diameter /2
= 5 cm.
Hence found .
Thank you !
PLEASE MARK AS BRAINLIEST...☺️
Akshaymas:
Please mark as Brainliest
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