Question

A triangle ABC is drawn to circumscribe a circle of radius 3cm. such that the segment BD and DC into which BC is divided by the point of contact Dare of length 9cm and 3cm. respectively (see adjacent figure). find the side AB and AC​

Answer 1

Answer:

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Answer 2

Answer:

54=

(x+15)(9)(6)(x)

Squaring both sides, we have

54

2

=54x(x+15)

x

2

+15x−54=0

Solve this quadratic equation and find the value of x.

x

2

+18x−3x−54=0

x(x+18)−3(x+18)=0

(x−3)(x+18)=0

Either x=3 or x=−18

But x cannot be negative.

So, x=3

Answer :-

AB=x+6=3+6=9cm

AC=x+9=3+9=12cm

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