Question

a triangle ABC is inscribed in a circle if sum of the squares of sides of a triangle is equal to twice the square of the diameter then what is sin^2 A + sin^2 B + sin^2 C is equal to what

Answer 1

Answer: 2

Step-by-step explanation:

we know that ,

a=2RsinA

b=2RsinB

c=2RsinC

Given:

2(2R)^2=a^2+b^2+c^2

⇒8R^2=4R^2(sin^2A+sin^2B+sin^2C)

⇒sin^2A+sin^2B+sin^2C=2