. A triangle ABC is right angled at A. AL is drawn perpendicular to BC. Prove that ∠ =
∠
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A triangle ABC is right angled at A. AL is drawn perpendicular to BC. Prove that ∠BAL=∠ACB.
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In △ABL,
∠BAL+∠ALB+∠B=180o
∠BAL+90o+∠B=180o
∠BAL=90o−∠B ......(1)
In △ABC,
∠A+∠B+∠C=180o
∠B+∠C=90o
∠C=90o−∠B
∠ACB=90o−∠B .......(2)
From 1 and 2, we get,
∠BAL=∠ACB
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