Question

A triangle ABC is right angled at A. L is a point on BC such that AL perpendicular TO BC. prove that angle BAL= angle ACB.

Answer 1

In ΔCAB 
∠C + ∠B + ∠CAB= 180

in ΔBLA
∠B + ∠BLA + ∠BAL = 180

comparing both 
∠ACB = ∠BAL

∠BLA = ∠BAC = 90 

Answer 2

"Triangles BLA and BAC is right angled with angle B. The other Angle in each is equal. Angle BAL and angle ACB are the same.

In ΔCAB

∠C + ∠B + ∠CAB = 180

In ΔBLA

∠B + ∠BLA + ∠BAL = 180

Comparing both

∠ACB = ∠BAL

∠BLA = ∠BAC = 90

Therefore the answer will be 90

"