Question

A triangle ABC is right angled at B ; find the value of (SecA•SinC - tanA•tanC)/sinB

Answer 1

Answer:

zero(0)

Step-by-step explanation:

secA×sinC-tanA×tanC÷sinB

h/p×p/h - b/p×p/b ÷ sinB

1-1÷ sinB

0÷sinB

0

Answer 2

HERE IS YOUR ANSWER

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