A triangle ABC is right-angled at C. If AB = 25m and AC= 15m, then find the length of BC.
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By P.G.T theorem
AB^2=BC^2+AC^2
25^2=BC^2+15^2
625=BC^2+225
625-225=BC^2
400=BC^2
√400=BC
20=BC
Answered by
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Answer:
AB²= 20 m
Step-by-step explanation:
By Pythagorus theorm,
AB² = AC²+BC²
25²m= 15²m+BC²
BC²= 625 - 225
BC²= 400(20×20)
BC²=20m
hope it helps you
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