A triangle ABC is such that sin(2A + B) =1/2 . If A, B, C are in A.P. then the angle A, B, C are
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Answer:
A,B,C ARE 45° ,60°,75°
Step-by-step explanation:
sin(2A+B) = 1/2
2A+B =sin `¹ (1/2)
2A+B = 30 (or) 150 ------(1)
In a triangle sun of interior angles is equal to 180
A+B+C = 180 ------(2)
Given ,
A,B,C are in A. P
then 2B = A+C --------(3)
put ,
(3) in(2)
2B +B = 180
3B = 180
B = 60°
If B is 60 then 2A + B = 30 is not possible
So,
2A + B = 150
2A + 60 = 150
2A = 90
A = 45°
put A= 45 and B = 60 in (2)
45+60+C = 180
105 + C = 180
C = 75°
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