Question

A triangle ABC , right angled at A . L is a point on BC such that AL is perpendicular to BC . Prove that angle BAL = angle ACB


Plese help gyus

Answer 1

Hi Dear ! 
________________________________________________________
In ΔCAB 

∠B + ∠C  + ∠CAB = 180° --(1) 

In ΔBLA 

∠B + ∠BLA  + ∠BAL = 180° --(2) 

By 1 and 2 we get , 

∠B + ∠C  + ∠CAB = ∠B + ∠BLA  + ∠BAL

∠C + ∠CAB = ∠BLA + ∠BAL 

[∠BLA = ∠BAC ...(90°0) ]

so, 
∠ACB = ∠BAL 

Answer 2

hey mate !!❤✌
here's ur answer ✍✍✍

➡️ Refer to attachment

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