Question

a triangle ABC with sides 5 cm 12 cm and 13 cm is revolved about the sides 12 CM.

Find :- volume of the solid so obtained​

Answer 1

Let hypotenuse =13cm

given triangle revolves around 12cm

radius=5cm

height=12cm

volume=1/3PI×r^2×H

volume=1/3×PI×5×5×12

vol.=100PIcm ^3 (nearly)

second case,

r=12cm

h=5cm

vol.=1/3×PI×12×12×5

vol.=240PI cm^3

Answer 2

Answer:

let hypotenuse =13cm

given triangle revolves around 12cm

radius=5cm

height=12cm

volume=1/3PI×r^2×H

volume=1/3×PI×5×5×12

vol.=100PIcm ^3 (nearly)

second case,

r=12cm

h=5cm

vol.=1/3×PI×12×12×5

vol.=240PI cm^3

the ratio is 100/240

5:12

Step-by-step explanation: