Question

A triangle and a parallelogram allelegram have some bars and same
ares if sides of triangle are
are 26 cm 28.m and 30cm.
and parallele from stands on have 28cm , find height
of parallelogrlim (4)​

Answer 1

Answer:

Step-by-step explanation:

Sides of the triangle are a = 26\ cm,b= 28\ cm\ and\ c =30\ cm.

Then, calculating the area of the triangle:

So, the semi-perimeter of triangle ABE,

s = \frac{a+b+c}{2} = \frac{28+26+30}{2} = 42\ cm.

Therefore, its area will be given by the Heron's formula:

A = \sqrt{s(s-a)(s-b)(s-c)}

    = \sqrt{42(42-28)(42-26)(42-30)}

    = \sqrt{42(14)(16)(12)} = \sqrt{112896} = 336\ cm^2

Given that the area of the parallelogram is equal to the area of the triangle:

Area\ of\ Parallelogram = Area\ of\ Triangle

\implies base\times corresponding\ height = 336\ cm^2

\implies 28\times corresponding\ height = 336\ cm^2

\implies height = \frac{336}{28} = 12cm.

Answer 2

Answer:

The height of the parallelogram is 12 cm

Step-by-step explanation:

S = (a+b+C)/2 = ( 26+28+30)/2 = 42 cm.

A =

$\sqrt{s(s - a)(s - b)(s - c)}$

here.

a=26, b=28, C=30

so, A =

$\sqrt{42(42 - 26)(42 - 28)(42 - 30)}$

=

$\sqrt{112896}$

= 336 cm

AREA OF PARALLELOGRAM = AREA OF TRIANGLE

=> base × corresponding height = 336 cm

=> 28 × corresponding height = 336 cm

=> height = 336/28 = 12 cm