Question

a triangle and a parallelogram are constructed on the same base such that their areas are equal if the altitude of the parallelogram is 100 M then find the altitude of the triangle

Answer 1

Let the triangle and parallelogram have common base b,
let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m),
$area \: of \: triangle = 12 \times b \times h1$
$area \: of \: rectangle = b \times h2$
$as \: per \: question$
$12 \times b \times h1 = b \times h2$
$12 \times b \times h1 = b \times 100h1 = 100 \times 2 = 200m$