Question

A triangle and a parallelogram are formed between two parallel and have a common base what will be the ratio of their areas​

Answer 1

Step-by-step explanation:

2:3 is the correct answer

Answer 2

The ratio of area of triangle to the area of parallelogram=1:2

Step-by-step explanation:

Let a triangle APB and a parallelogram ABCD are formed between two parallel lines  AB and CD and lie on common base BC.

Theorem:When a triangle and  a parallelogram lie on same base and formed between same parallel lines then the area of triangle is equal to half of the area of parallelogram.

By this theorem

Area of triangle APB=$\frac{1}{2}Ar(ABCD)$

Let area of parallelogram ABCD=x square units

Then, area of triangle APB=$\frac{1}{2}x$ square units

$\frac{Area\;of\;triangle\;APB}{area\;of\;parallelogram\;ABCD}=\frac{\frac{1}{2}x}{x}=\frac{1}{2}$

Hence, the ratio of area of triangle to the area of parallelogram=1:2

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https://brainly.in/question/11237218:answered by Brainly hulk