Question

a triangle and a parallelogram are on equal base and between the same parallel, the ratio of their areas is -- 1:2 , 1:1 , 2:1 , 3:1 .

Answer 1

triangle ABE =1/2 AREA OF PARALLELOGRAM
hence ratio will be 1:2

Answer 2

Here ABCD is the given llgm and ADC is the given traingle .

Draw AE as the height of triangle ADC.

Clearly the distance between two ll lines are equal thus, AE is the height of llgm ABCD also.

Thus ar. of ADC/ ar. of ABCD = 1/2× AD×AE ÷ AD×AE = 1:2

THUS 1:2 is the required ratio.

$\huge\boxed{hope\:it's \:help}$