Question

A triangle and a parallelogram have same base and the same area. If the sides of a triangle are 13,14, 15 cm
and the parallelogram stands on the bass
14 cm , find the height of the parallelogram
​

Answer 1

Answer:

6 cm

Step-by-step explanation:

The area of triangle and the parallelogram is same

So, first let is take the area of the triangle which will be same of the parallelogram

s=15+14+13/2

= 42/2=21

A= s(s-a)(s-b)(s-c)*1/2

=21(2115)(21-14)(21-13)*1/2

=21*6*7*8*1/2

84 cm2

So, area of triangle = parallelogram = 84 cm2

b=14cm

Area of parallelogram = b*h

84=14*h

h=84/14=6cm

Hence , the height of the parallelogram is 6cm

Answer 2

Answer is 6 cm

Step-by-step explanation:

Area of triangle = Area of parallelogram

s = a+b+c /2 = b×h

13+14+15/2 = 14×h

42/2 = 14 ×h

21 = 14 × h

√21(21-13) (21-14) (21-15) = 14 × h

√21× 8 × 7 × 6 = 14 × h

√3×7×2×2×2×7×2×3 = 14 × h

3×7×2×2 = 14×h

h= 84/14

h= 6cm