a triangle and a parallelogram have the same base and equal areas of the altitude of the triangle is 20 cm find the altitude of the parallelogram
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area of llgm =b×height
=b×height
area of llgm =area of triangle
b×h=1/2×b×10
h=10cm
=b×height
area of llgm =area of triangle
b×h=1/2×b×10
h=10cm
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