A triangle and a parallelogram have the same base and same area. If the sides of the triangle are 15 cm, 14 cm and 13 cm and the parallelogram stands on the base 15 cm, find the height of the parallelogram
Answers
☞ Height of the triangle = 5.6 cm
Area of parallelogram = Area of triangle
✭ Base × Height = Area of triangle
✭ 15cm × Height = Area of triangle
✭ Height =
➢ Height of the parallelogram?
We know that,
Area of triangle =
❍ Here, s represents semi-perimeter, and a, b, c are the sides of the triangle.
◕ a = 15 cm
◕ b = 14 cm
◕ c = 13 cm
Area of triangle =
➳ Area=
➳ Area =
➳ Area =
➳ Area =
Now,
Answer:
Step-by-step explanation:
Given :-
Sides of triangle = 15 cm, 14 cm and 13 cm
Base of parallelogram = 15 cm
To Find :-
Height of parallelogram
Formula to be used :-
Area of triangle = √s(s - a) (s - b) (s - c)
Area of parallelogram = Base × height
Solution :-
Semi perimeter = 15 + 14 + 13/2 = 42/2 = 21
Now, Area of triangle = √s(s - a) (s - b) (s - c)
⇒ Area of triangle = √21(21 - 15) (21 - 14) (21 - 13)
⇒ Area of triangle = √21(6) (7) (8)
⇒ Area of triangle = 3 × 7 × 3 × 2 × 7 × 2 × 2 × 2
⇒ Area of triangle = 3 × 7 × 2 × 2
⇒ Area of triangle = 84 cm²
Now,
Let h be the height of the parallelogram,
Area of parallelogram = Base × height
⇒ Area of parallelogram = 15 × h
⇒ Area of parallelogram = 15h cm²
Its given that
Area of triangle = Area of parallelogram
⇒ 84 = 15 h
⇒ 84/15 = h
⇒ h = 5.6 cm
Hence, the height of the parallelogram is 5.6 cm.