Question

a triangle and a parallelogram have the same base and the same area if the sides of the triangle are 126cm, 120 CM and 130 cm and the parallelogram stands on the base 120 CM find the the corresponding height of the parallelogram ​

Answer 1

Answer:

Here is your answer.

Semi perimeter = 180

Area of triangle :-

\begin{lgathered}= \sqrt{180 \times (180 - 120) \times (180 - 126) \times (180 - 130)} \\ = \sqrt{188 \times 68 \times 62 \times 58} \\ = 8 \sqrt{718301}\end{lgathered}

=

180×(180−120)×(180−126)×(180−130)

=

188×68×62×58

=8

718301

area of parallelogram = base × height

\begin{lgathered}8 \sqrt{718301} = 120 \times h \\ h = 56.51\end{lgathered}

8

718301

=120×h

h=56.51

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Answer 2

Answer:

Semi perimeter s of triangle = (126+120+130)/2 = 188 cm

Area of triangle =

\sqrt{188*(188-120)(188-126)(188-130)}=\\\\\sqrt{188*68*62*58}=8\sqrt{718301}

Area of parallelogram = base*altitude

8\sqrt{718301}=120*altitude\\

Altitude of parallelogram = 56.501 cm aproximately

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