Question

A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 13cm, 14cm and 15cm and the parallelogram stand on the base 14cm, find the height of the parallelogram. ​

Answer 1

hey mate gere is your answer .....

Given,

Sides of tri.- 13,14 and 15 cm

base of //^gm = 14 cm

☘ By Heron's Formula.-

s= (13+14+15) cm/2=42/2= 21 cm.

>> √ s(s-a)(s-b)(s-c)

>> √ 21(21-13)(21-14)(21-15)

>> √ 21× 8 × 7 × 6

>> √ 3×7× 4×2 × 3×2×7

>> 168 cm^2

☘ Now,h of //^gm.-

>168=14×h

> 168/14=h

> h= 12 CM

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Answer 2

Answer:

6

Step-by-step explanation:

a=15cm

b=13cm

c=14cm

s=a+b+c/2

=>s=15+13+14/2

=>s=42/2

=>s=21cm

$\sqrt{ } {s(s - a)(s - b)(s - c)} \\ \sqrt{21 \times 21 - 15 \times 21 - 13 \times 21} \\ \sqrt{21 \times 6 \times 8 \times 7 } \\ \sqrt{3 \times 7 \times 3 \times 2 \times 2 \times 2 \times 2 \times 7} \\ 3 \times 7 \times 2 \times 2 \\ = 84cm {}^{2}$

AREA OF TRIANGLE=AREA OF PARALLELOGRAM

According to question:-

84=base×height

84=14×height

84/14=height

6=height