A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm. 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find the height of the parallelogram
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Answered by
1
Answer:
Hi friends
Step-by-step explanation:
Let the Length of the sides of the triangle are a=26 cm, b=28 cm and c=30 cm.
Let s be the semi perimeter of the triangle.
s=(a+b+c)/2
s=(26+28+30)/2= 84/2= 42 cm
s = 42 cm
Using heron’s formula,
Area of the triangle = √s (s-a) (s-b) (s-c)
= √42(42 – 26) (46 – 28) (46 – 30)
= √42 × 16 × 14 × 12
=√7×6×16×2×7×6×2
√7×7×6×6×16×2×2
7×6×4×2= 336 cm²
Let height of parallelogram be h.& Base= 28 (given)
Area of parallelogram = Area of triangle (given)
[Area of parallelogram =base× height]
28× h = 336
h = 336/28 cm
h = 12 cm
Hence,
The height of the parallelogram is 12 cm.
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Answered by
0
Answer:
12
Step-by-step explanation:
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