A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 13cm, 14cm and 15cm and the parallelogram stands on the base 14cm , find the height of the parallelogram.
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Given sides of the triangle are 13cm,14cm,15cm
We know that the area of the triangle is s(s−a)(s−b)(s−c)
where a,b,c are the sides of the triangle and
s=2a+b+c=213+14+15=21
Therefore, the area of the triangle is 21(21−13)(21−14)(21−15)=7056=84 -------(1)
Given that base of the parallelogram is 14cm
Given that the triangle and the parallelogram have the same area.
Therefore, area of parallelogram = area of triangle
⟹base * height = area of triangle
⟹14 * height = area of triangle
⟹14 * height = 84 (from (1))
⟹height=1484=6cm
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