Question

A triangle and a parallelogram shares same base .Also, area of the triangle is equal to
the area of the parallelogram. If area of the triangle is 25√3 cm2 and base of the
parallelogram is 5 cm , find the height of the parallelogram.


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Answer 1

Answer:-

According to the Question

It is given that triangle and a parallelogram shares same base .Also, area of the triangle is equal to the area of the parallelogram. If area of the triangle is 25√3 cm2 and base of the parallelogram is 5 cm . We have to calculate the height of parallelogram. So , Let's begin

Let the height of parallelogram be h cm.

$:\implies$ Area of ∆ = Area of Parallelogram (given)

Substitute the value we get

$:\implies$ 25/√3 = 5 × h

$:\implies$ h × 5 = 25/√3

$:\implies$ h = 25/5 × 1/√3

$:\implies$ h = 5 × 1/√3

$:\implies$ h = 5/√3 cm or

$:\implies$ h = 5√3/3 cm

• Hence, the height of the Parallelogram is 5/√3 or 5√3/3.

Answer 2

Given :-

A triangle and a parallelogram shares same base .Also, area of the triangle is equal to  the area of the parallelogram. If area of the triangle is 25√3 cm² and base of the  parallelogram is 5 cm

To Find :-

height of parallelogram

Solution :-

We know that

Area of triangle = Area of parallelogram

1/2 × b × h = b × h

25/√3 = 5 × h

25/√3/5 = h

25/√3 × 1/5 = h

3/√3 × 1/1 = h

3/√3 = h