Question

a triangle and a parallelogram stand on the same base and are equal in area is 10 sides of triangle are 40 cm, 32 cm and 24 cm and the base of parallelogram is 40 cm find the corresponding height of parallelogram . answer with figure who will give me correct answer I will mark as brainliest​

Answer 1

Solution :-

Lengths of the sides of the triangle :

• a = 40 cm

• b = 32 cm

• c = 24 cm

Semi - perimeter (s) = (a + b + c)/2

⇒ s = (40 + 32 + 24)/2

⇒ s = 96/2

⇒ s = 48

We know that

Area of the triangle = $\sf \sqrt{s(s - a)(s - b)(s - c}$

$\sf = \sqrt{48(48 - 40)(48 - 32)(48 - 24)} \\ \\ \sf = \sqrt{48(8)(16)(24)} \\ \\ \sf = \sqrt{384(384)} \\ \\ \sf = \sqrt{ {384}^{2} } \\ \\ \sf = 384 \: cm^{2}$

Area of the triangle = 384 cm²

Triangle and parallelogram stand on same base

That means lengths of the corresponding bases are equal

Length of the base of the parallelogram (b) = 40 cm

Let the height of the parallelogram be 'h' cm

Given

Area of the Parallelogram = Area of the triangle

⇒ bh = 384 cm²

⇒ 40h = 384

⇒ h = 384/40

⇒ h = 9.6 cm

Therefore the height of the parallelogram is 9.6 cm

Answer 2

Answer:

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