Question

A triangle and a parellogram are constructed on the same base and their areas are equal. If the altitude of parallelogram is 100m then find altitude of triangle

Answer 1

Let the triangle and parallelogram have common base b,

let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then 

Area of triangle    = ½*b*h1

Area of rectangle  = b*h2

As per Given,

½*b*h1=b*h2

½*b*h1=b*100

h1=200m