Question

A triangle and parallelogram are constructed on the same base such that their area are equal. If the altitudes of the parallelogram is 100m, then find the altitude of the triangle.​

Answer 1

$\huge\underline\mathrm{SOLUTION:-}$

AnswEr:

• The altitude of the triangle = 200 metres.

Given That:

• A triangle and parallelogram are constructed on the same base such that their area equal.

Need to find:

• The altitude of the triangle = ?

ExPlanation:

Let,

• Triangle and parallelogram have common base b,
• And, altitude of the triangle is h1 and of parallelogram is h2(that is equal to 100 metres).

ThereFore:

Area of triangle = 1/2 × b × h1

Area of parallelogram = b × h2

According to the given condition:

➠ 1/2 × b × h1 = b × h2

➠ 1/2 × b × h1 = b × 100

➠ h1 = 200 metres

• Hence, the altitude of the triangle = 200 metres

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