a triangle and parallelogram are constructed on the same base such that their area equal .if the altitude of the parallelogram is 100 m then find the altitude of the triangle.
Answers
Answered by
0
Heya,
Solution to your question is:-
Let the triangle and parallelogram have common base b,
let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then
Area of triangle = 1/2×b×h1
Area of ||gm = b*h2
As per Given,
1/2*b*h1=b*h2
1/2*b*h1=b*100
【 h1=200】 ANSWER...
HOPE THIS HELPS YOU:-))
@Ashu
Solution to your question is:-
Let the triangle and parallelogram have common base b,
let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then
Area of triangle = 1/2×b×h1
Area of ||gm = b*h2
As per Given,
1/2*b*h1=b*h2
1/2*b*h1=b*100
【 h1=200】 ANSWER...
HOPE THIS HELPS YOU:-))
@Ashu
Similar questions