Question

a triangle and parallelogram are constructed on the same base such that their areas are equal if the altitude of a parallelogram is 100 metre the altitude of the triangle is​

Answer 1

Answer:

Step-by-step explanation:

answer is-200m

1/2*b*h=b*h

cutting base from both the sides

1/2*h=100

h=200m..

Answer 2

✬ $\texttt{Altitude = 200 m}$ ✬

Step-by-step explanation:

Given:

• A triangle and parallelogram are constructed on same base.
• Area of triangle and parallelogram are equal.
• Measure of altitude of parallelogram is 100 m.

To Find:

• What is the altitude of the triangle ?

Solution: Let the measure of bases of both the triangle and parallelogram be b cm.

As we know that

★ Area of ||gm = Base $\times$ Height ★

$\implies{\rm }$ Area of ||gm = b $\times$ 100.........(1)

★ Area of ∆ = 1/2(Base)(Height)★

$\implies{\rm }$ Area of ∆ = $</strong><strong>\</strong><strong>b</strong><strong>f</strong><strong>\dfrac{1}{2}$ $\times$ b $\times$ h.........(2)

Since, Both their areas are equal therefore,

• Equation 1 = Equation 2

➟ b $\times$ 100 = $\dfrac{1}{2}$ $\times$ b $\times$ h

➟ 100 = $\dfrac{h}{2}$

➟ 100 $\times$ 2 = h

➟ 200 m = h

Hence, the meaure of altitude of triangle is 200 m.