Math, asked by DhairyaJain076, 16 days ago

A triangle and parallelogram have the same base and the same area. If the sides of the triangle are 34 cm, 42 cm and 20 cm, then the height of parallelogram having base 42 cm, is equal to

Answers

Answered by amitnrw
3

Given : A triangle and parallelogram have the same base and the same area.

The sides of the triangle are 34 cm, 42 cm and 20 cm,

To Find :  the height of parallelogram having base 42 cm

Solution:

The sides of the triangle are 34 cm, 42 cm and 20 cm,

s = ( 34 + 42 + 20)/2 = 48

Area  = √(48)(48 - 34)(48 - 42) (48 - 20)

=> Area = √48 * 14 * 6 * 28

=> Area = √2 * 4 * 6 *2 * 7 * 6 * 4 * 7

=> area = 2 * 4 * 6 * 7

=> Area = 42 * 8

Area of parallelogram = Base * height

Hence height of the parallelogram = 8 cm

Learn More:

13.Area enclosed between the lines x+2y-4 =0 and x+2y-2 =0 and ...

brainly.in/question/21475622

find the are of the region in the first quadrant enclosed by the x-axis ...

brainly.in/question/2705769

Answered by RvChaudharY50
0

Solution :-

Semi - perimeter of given ∆ = s = sum of all sides / 2 = 34 + 42 + 20 / 2 = 48 cm

now,

→ Area of ∆ = √[s * (s - a) * (s - b) * (s - c)]

→ Area of ∆ = √[48 * (48 - 34) * (48 - 20) * (48 - 42)]

→ Area of ∆ = √[48 * 14 * 28 * 6]

→ Area of ∆ = √[6 * 8 * 2 * 7 * 4 * 7 * 6]

→ Area of ∆ = 6 * 7 * 8

→ Area of ∆ = 336 cm² .

now, let us assume that the height of parallelogram is equal to h cm .

then,

→ Area of ll gm = 336 cm²

→ Base * height = 336

→ 42 * h = 336

→ h = 8 cm (Ans.)

Hence, the height of parallelogram is equal to 8 cm .

Learn more :-

Diagonals AC and BD of quadrilateral ABCD meet at E. IF AE = 2 cm, BE = 5 cm, CE = 10 cm, 8 सेमी.

https://brainly.in/question/27312677

Let abcd be a rectangle. the perpendicular bisector of line segment bd intersect ab and bc in point e and f respectively...

https://brainly.in/question/27813873

Similar questions