Question

A triangle and the parallelogram have same base and same parallel than prove that area of triangle is half of the area of parallelogram​

Answer 1

Answer:

Draw AL⊥BC and DM⊥BC, meeting BC produced in M.

Since, A, E and D are collinear and BC∥AD

Therefore,

AL=DM

Now,

ar(△ABC)=

2

1

(BC×AL)

ar(△ABC)=

2

1

(BC×DM)

ar(△ABC)=

2

1

ar(∥

gm

BCDE)

Answer 2

ok..... .....................