Question

A triangle has a perimeter of 26 cm and sides of length x cm, (x + 3) cm, and (x + 5) cm. What is the value of x

Answer 1

Step-by-step explanation:

perimeter of triangle = 26 cm

perimeter of triangle = 26 cmsum of all sides = 26 cm

perimeter of triangle = 26 cmsum of all sides = 26 cm x + (x+3) + (x+ 5) = 26cm

perimeter of triangle = 26 cmsum of all sides = 26 cm x + (x+3) + (x+ 5) = 26cm x+x+3+x+5 = 26 cm

perimeter of triangle = 26 cmsum of all sides = 26 cm x + (x+3) + (x+ 5) = 26cm x+x+3+x+5 = 26 cm 3x + 8 = 26 cm

perimeter of triangle = 26 cmsum of all sides = 26 cm x + (x+3) + (x+ 5) = 26cm x+x+3+x+5 = 26 cm 3x + 8 = 26 cm 3x = 26 - 8

perimeter of triangle = 26 cmsum of all sides = 26 cm x + (x+3) + (x+ 5) = 26cm x+x+3+x+5 = 26 cm 3x + 8 = 26 cm 3x = 26 - 8 3x = 18

perimeter of triangle = 26 cmsum of all sides = 26 cm x + (x+3) + (x+ 5) = 26cm x+x+3+x+5 = 26 cm 3x + 8 = 26 cm 3x = 26 - 8 3x = 18 x = 18÷ 3

perimeter of triangle = 26 cmsum of all sides = 26 cm x + (x+3) + (x+ 5) = 26cm x+x+3+x+5 = 26 cm 3x + 8 = 26 cm 3x = 26 - 8 3x = 18 x = 18÷ 3 x = 6 ANSWER

Answer 2

FINAL ASNWER:-

$x=6$

TO FIND:-

value of x

GIVEN:-

• triangle has a perimeter of 26 cm

• sides of length x cm, (x + 3) cm, and (x + 5) cm

SOLUTION:-

let the side of ΔABC

$AB=x\\BC=x+3\\AC=x+5$

perimeter of triangle = AB + BC + AC

$26=x+x+3+x+6\\26=x+x+x+3+5\\26=3x+8\\3x=26-8\\3x=18\\x=\frac{18}{3}\\x=6$

$AB=6cm$

$BC=x+3$ ⇒ $9cm$

$AC=x+5$ ⇒ $11cm$

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