Question

A triangle has a perimeter of 3z-6d+5 and has sides of length 3z-4 and d+2. What is the length of the third side?

Answer 1

Step-by-step explanation:

perimeter of triangle = sum of all the three sides

let the third side be x .

3z-6d+5= 3z-4+d+2 + x

3z-6d+5= 3z +d-2+ x

3z-6d+5-3z-d+2 = x

-7d +7 = x

7 - 7d = x

so length of third side is 7-7d

if something gets wrong it's due to typing but answer is correct ..