A triangle has a perimeter of 3z-6d+5 and has sides of length 3z-4 and d+2. What is the length of the third side?
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Step-by-step explanation:
perimeter of triangle = sum of all the three sides
let the third side be x .
3z-6d+5= 3z-4+d+2 + x
3z-6d+5= 3z +d-2+ x
3z-6d+5-3z-d+2 = x
-7d +7 = x
7 - 7d = x
so length of third side is 7-7d
if something gets wrong it's due to typing but answer is correct ..
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