Question

A triangle has a perimeter of 3z-6d+5 and has sides of length 3z-4 and d+2. What is the length of the third side?

Answer 1

Step-by-step explanation:

let a= 3z-4 b=d+2

We have

perimeter= 3z-6d+5

a+b+c= 3z-6d+5

3z-4+d+2+c= 3z-6d+5

c= -6d+5+4-d-2

= 7-7d