Question

A TRIANGLE HAS ALTITUDE 10M AND BASE 16M .FIND THE AREA OF TRIANGLE AND OPPOSITE SIDE.​

Answer 1

Answer:

AREA OF TRAINLE=80 m^2✔✔

OPPOSITE SIDE=

$2 \sqrt{41}$✔✔

Step-by-step explanation:

$area \: of \: triangle = \frac{1}{2} \times b \times h \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{2} \times 16 \times 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {80m}^{2} \\base \: of \: triangle = 8m \\ p = 10 \\ {h}^{2} = {p}^{2} + {b}^{2} \\ {h}^{2} = {10}^{2} + {8}^{2} \\ {h}^{2} = 164 \\ {h} = \sqrt{164} \\ h = 2 \sqrt{41}$

Answer 2

Answer:

Ar. of ∆ = 80m²

Opposite Side = 2√41 m

Step-by-step explanation:

Ar. of ∆ = 1/2 * b * h

= 1/2 * 16 * 10

= 80 m²

Base = 8m ; Perpendicular = 10m

h² = b² + p²

h² = 8² + 10²

h² = 164

h = √164

h = 2√41 m