Question

A triangle has an area of 90 square cm find the length of the base if the corresponding base is 3cm more then the height?
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Answer 1

Let the height be x then base wil be x+3

ATQ

1/2*(×*(x+3))

1/2(x^2+3x)

((x^2)/2)+(3x/2)=90

((x^2)/2)*2+(3x/2)*2=90*2

x^2+3x=180

x=12

Height=12

Base=12+3=15

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Answer 2

Answer:

15 cm.

Step-by-step explanation:

Assuming that the mentioned triangle is right-angled triangle, the area of the triangle can be written as

0.5XBaseXHeight= Area

But the question mentioned that the base= height + 3, so height= base - 3

Therefore, 0.5XBaseXBase-3=Area

0.5XBXB-3= 90

BXB-3B=180

B^2-3B-180=0

B= 15, -12

Since the base cant be a negative, the answer is 15cm.