A triangle has base (x + 2)cm and height (7 - x) cm, equation for area is .. plz ans
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Answer:
Step-by-step explanation:
Area of a triangle= 1/2×b×h
= 1/2× (x+2)(7-x)
=1/2(7x-x^2+14-2x)
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It is given that the base of the triangle is ( x + 2 ) cm and the height of the same triangle is ( x - 7 ) cm.
From the properties of triangle, we know :
On the basis of the formula given above,
Area of this triangle = ( 1 / 2 ) x base x hieght
Area of the triangle = - ( 1 / 2 ) x ( x + 2 ) x ( x - 7 ) cm²
Area of the triangle = - ( 1 / 2 ) x [ x( x - 7 ) + 2( x - 7 ) ] cm²
Area of the triangle = - 1 / 2 x ( x² - 7x + 2x - 14 ) cm²
= - 1 / 2 x ( x² - 5x - 14 ) cm²
Hence,
An equation on the basis of the given measurements for the area of the is - ( x² - 5x - 14 ) / 2 cm² or ( - x² + 5x + 14 ) / 2 cm²
From the properties of triangle, we know :
On the basis of the formula given above,
Area of this triangle = ( 1 / 2 ) x base x hieght
Area of the triangle = - ( 1 / 2 ) x ( x + 2 ) x ( x - 7 ) cm²
Area of the triangle = - ( 1 / 2 ) x [ x( x - 7 ) + 2( x - 7 ) ] cm²
Area of the triangle = - 1 / 2 x ( x² - 7x + 2x - 14 ) cm²
= - 1 / 2 x ( x² - 5x - 14 ) cm²
Hence,
An equation on the basis of the given measurements for the area of the is - ( x² - 5x - 14 ) / 2 cm² or ( - x² + 5x + 14 ) / 2 cm²
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