Question

A triangle has side 35cm,54cm and 61 cm long.find it's area. Also,find the samllest of its altitudes.

Answer 1

Answer:

Step-by-step explanation:

let the sides of the triangle are  a, b, c.

then, a= 35 cm, b= 54 cm, c= 61 cm.

according to heron's law, area of the triangle will be= $\sqrt{s(s-a)(s-b)(s-c)$

s is the semi perimeter of that trinagle, s= (35+54+61)/2

                                                      =150/2 = 75.

now the area is= $\sqrt{75(75-35)(75-54)(75-61)}$

→√(75×40×21×14)

→√882000

→√939.14 (approx.)

∴ the area of the triangle is 939.14 cm².

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