Question

A TRIANGLE HAS SIDE AB=4 CM ,BC=5CM,CA=9CM AND ITS ALTITUDE IS 10 CM .THEN FIND
1}PERIMETER
2}AREA​

Answer 1

Aloha!

Refer to attachment

Answer 2

ANSWER-

1}18 CM✔✔

2}45CM^2✔✔

Step-by-step explanation:

$in \: question \: there \: is \: some \: information \: given \: that$

□AB=4CM✔✔

□BC=5CM✔✔

□CA=9CM✔✔

□AD=10CM✔✔

WE HAVE TO FIND

○PERIMETER OF TRIANGLE=??

○AREA OF TRIANGLE=??

SO FIRST WE FIND

○PERIMETER OF TRIANGLE=AB+BC+CA

=4+5+9

=18CM

IN SECOND QUESTION WE HAVE TO FIND

○AREA OF TRIANGLE

$\frac{1}{2} \times b \times h \\ = \frac{1}{2} \times 9 \times 10 \\ = 45 {cm}^{2}$