A triangle has side length 18,24,30 .find the area of the triangle whose vertices are the incentre ,circumcentre and centroid of the triangle.
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s = 1/2( 18+24+30)
= 1/2 × 72
= 36
area = √36× ( 36-18)(36-24)(36-30)
= √ 36 ×18×12×6
= √ 18×2×18×2×6×6
= 18 ×2×6
= 36×6
= 216
= 1/2 × 72
= 36
area = √36× ( 36-18)(36-24)(36-30)
= √ 36 ×18×12×6
= √ 18×2×18×2×6×6
= 18 ×2×6
= 36×6
= 216
DINKARKUMARJHA:
wrong answers ....
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