Question

A triangle has sides 35 cm,54 cm and 61 cm long.Find it's area.Also find the smallest of it's altitude....​

Answer 1

Let

a = 35 cm

b = 54 cm

c = 61 cm

Perimeter = a + b + c

= 35 + 54 + 61

= 150 cm

S = Perimeter / 2 = 150 / 2 = 75 cm

Area = √[ s (S-a) (S-b) (s-c)]

=√[75(75-35) (75-54) (75-61)]

=√[75x40X21X14]

=√[5^3X3^2 x2^4X7^2]

= 5x3x2X2X7√5

= 420√5

=939.15cm2

smallest altitude is present on the longest side of the triangle

so ,

longest side = c = 61cm

Area = 1/2 x base x altitude

939.15= 1/2 X 61 X altitude

(939.15X2)/61 = altitude

so, shortest altitude = 30.79 cm

Answer 2

Answer:

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Step-by-step explanation:

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