Question

A triangle has sides 35 cm, 54 cm and 61 cm long. Find its area. Also, find the smallest of its altitudes.​

Answer 1

Answer:

Area = 939.15 cm2

smallest altitude=5366.57

Answer 2

Step-by-step explanation:

Let a=35cm

b=54cm

c=61cm

s=2a+b+c=235+54+61

 =2150

=75cm

Area of triangle =s(s−a)(s−b)(s−c)

=75(75−35)(75−54)(75−61)

=75×40×21×14

=25×3×4×10×7×3×7×2

=5×5×3×3×2×2×7×7×2×2×5×5

=5×3×2×7×2×5

=30×70

=2100cm2

Smallest altitude will be the altitude on greatest side

So, Area of triangle =2100

⇒1/2×61×h=2100

h= 2100×2/61

h =68.85 cm (approx)