Math, asked by ambongdusag, 5 months ago

A triangle has sides equal to 4 m, 11 m and 8 m. Find its angles (round answers to 1 decimal place).​

Answers

Answered by yogitamil99
0

ANSWER :

ANSWER : a = 4; b = 8; c = 11

ANSWER : a = 4; b = 8; c = 11

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C)

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C)

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C) 112 = 42 + 82 - 2*4*8 * cos(C)

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C) 112 = 42 + 82 - 2*4*8 * cos(C)121 = 16 + 64 - 64 * cos(C) Sqare values

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C) 112 = 42 + 82 - 2*4*8 * cos(C)121 = 16 + 64 - 64 * cos(C) Sqare values121 - 16 - 64 = -64 * cos(C) Subtract a and b from both sides

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C) 112 = 42 + 82 - 2*4*8 * cos(C)121 = 16 + 64 - 64 * cos(C) Sqare values121 - 16 - 64 = -64 * cos(C) Subtract a and b from both sides41 = -64 * cos(C)

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C) 112 = 42 + 82 - 2*4*8 * cos(C)121 = 16 + 64 - 64 * cos(C) Sqare values121 - 16 - 64 = -64 * cos(C) Subtract a and b from both sides41 = -64 * cos(C) 41 / -64 = cos(C) Divide both sides by -2ab

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C) 112 = 42 + 82 - 2*4*8 * cos(C)121 = 16 + 64 - 64 * cos(C) Sqare values121 - 16 - 64 = -64 * cos(C) Subtract a and b from both sides41 = -64 * cos(C) 41 / -64 = cos(C) Divide both sides by -2abC = cos-1(-0.641) Inv cos

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C) 112 = 42 + 82 - 2*4*8 * cos(C)121 = 16 + 64 - 64 * cos(C) Sqare values121 - 16 - 64 = -64 * cos(C) Subtract a and b from both sides41 = -64 * cos(C) 41 / -64 = cos(C) Divide both sides by -2abC = cos-1(-0.641) Inv cos

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C) 112 = 42 + 82 - 2*4*8 * cos(C)121 = 16 + 64 - 64 * cos(C) Sqare values121 - 16 - 64 = -64 * cos(C) Subtract a and b from both sides41 = -64 * cos(C) 41 / -64 = cos(C) Divide both sides by -2abC = cos-1(-0.641) Inv cos

ANSWER : a = 4; b = 8; c = 11 c2 = a2 + b2 - 2ab cos(C) 112 = 42 + 82 - 2*4*8 * cos(C)121 = 16 + 64 - 64 * cos(C) Sqare values121 - 16 - 64 = -64 * cos(C) Subtract a and b from both sides41 = -64 * cos(C) 41 / -64 = cos(C) Divide both sides by -2abC = cos-1(-0.641) Inv cos Repeat for 1 more angle then use Pythag for the third

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Answered by sakshimanve
0

Answer:

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