Question

A triangle has sides measure 40 m 24 m and 32 m find the area of triangle

Answer 1

First,

Semi-Perimeter =  $\frac{40+24+32}{2} = \frac{96}{2} = 48$


Now,

Heron's Formula ,


Area  = $\sqrt{s(s-a)(s-b)(s-c)}$

Here,

Area  = $\sqrt{48(48-24)(48-40)(48-32)}$

Area  =  $\sqrt{48 * 24* 8*16}$

Area   =  [tex] \sqrt{147456} [/tex]

Area =  $384m^{2}$



i hope this will help you


-by ABHAY

Answer 2

An alternative approach to Heron's formula:
40 ,32 , 24 are Pythagorean triplets
40^2 = 32^2 + 24^2
1600 = 1024 + 576 = 1600
Hence it is a right angled triangle.
Area = 1/2 * b*h = 1/2 * 32 * 24 = 384 m^2.
Hope it helps.