Question

A triangle has sides of length 11 cm, 12 cm, and 11 cm. The area of this triangle is​

Answer 1

Answer:

height multiple by base of triangle (height)× (base)=(area)

=11×12=132

Step-by-step explanation:

area of triangle=height×base

=11×12

=132

Answer 2

Step-by-step explanation:

Heron's formula

s = (11 + 12 +11)/2

$\sqrt{17 \times (17 - 11) \times(17 - 12) \times (17 - 11)}$

$\sqrt{17\times 6 \times 5 \times 6}$

$\sqrt{17 \times 2 \times 3\times 5\times 2 \times 3}$

$2 \times 3 \sqrt{17 \times 5}$

$6 \sqrt{85}$