A triangle has sides of length 3÷5m,4÷5m and 1m.find its perimeter.
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Answered by
1
Sum of the sides are perimeter
P = 4/5 + 3/5 + 1
= 4/5 + 3/5 + 5/5
= (4+3+5)/5
= 12/5
P = 4/5 + 3/5 + 1
= 4/5 + 3/5 + 5/5
= (4+3+5)/5
= 12/5
Answered by
0
Bro, we know that sum of all side of triangle is equal to the perimeter of triangle
Then, perimeter= 3/5+4/5+1
=3+4+5/5
=12/5
Hence ,the perimeter of triangles= 12/5
HOPE IT HELP
Then, perimeter= 3/5+4/5+1
=3+4+5/5
=12/5
Hence ,the perimeter of triangles= 12/5
HOPE IT HELP
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