A triangle has sides of lengths 6, 8 and 10. Find the distance between the center of its inscribed circle and the center of the circumscribed circle.
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ABC is an equilateral triangle
∠ACD = 60°
∠OCD = ∠ACD / 2
= 30°
In triangle OCD,
cos 30°= CD / OC
=> √3 / 2 = 3 / r
=> r = 3 x 2 /√3
= 6 / √3
= 2√3 cm
= 3.4641 cm
∠ACD = 60°
∠OCD = ∠ACD / 2
= 30°
In triangle OCD,
cos 30°= CD / OC
=> √3 / 2 = 3 / r
=> r = 3 x 2 /√3
= 6 / √3
= 2√3 cm
= 3.4641 cm
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