Math, asked by nekabarizina, 6 months ago

A triangle has sides (x+20), (x+30) and (3x-10). What is the value of x

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Answered by anu4248
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Answered by Anonymous
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\large {\rm {\purple {\underbrace {\pink {Question}}}}}

If the measures of the three angles of a triangle are (x+20), (x+30) and (3x-10). What is the value of x ?

\large {\rm {\purple {\underbrace {\pink {Answer}}}}}

x + 20 + x + 30 + 3x - 10 = 180

5x = 180 - 40

5x = 140

x = \large \frac{140}{5}

x = 28

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