Question

A triangle has vertices at A (0, 6) B (12,0) and C(-2, 2). Find the equation of the perpendicular bisector to BC

Answer 1

Answer:

let a point D on BC which join AD

For the coordinate of D

X=X1+ X2/2

=12- 2/ 2

= 5

Y= Y1+ Y2/2

=0+2/2

=1