a triangle have sides of 25 mm,35 mm,and 50mm.find its area
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Answer:
area of Δ = √[s(s-a)(s-b)(s-c)]
here S = semiperimeter.
then S = 25+35+50/2 = 110/2= 55
then Ar = √[55(55-25)(55-35)(55-50)] = √55(30×20×5)= √16500 = 406.2 mm^2 answer
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