Question

A triangle have the same base and same area if the sides of the triangle are 15cm,14cm and 13cm and the pallerogram stands on the base 15cm find the hight of the pallogram

Answer 1

Answer ____,,

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:s= (a+b+c)/2 = (13 + 14 + 15)/2 = 21 cm

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:s= (a+b+c)/2 = (13 + 14 + 15)/2 = 21 cmWe know,

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:s= (a+b+c)/2 = (13 + 14 + 15)/2 = 21 cmWe know,The area of a triangle is:

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:s= (a+b+c)/2 = (13 + 14 + 15)/2 = 21 cmWe know,The area of a triangle is:A = [s(s-a)(s-b)(s-c)]^1/2

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:s= (a+b+c)/2 = (13 + 14 + 15)/2 = 21 cmWe know,The area of a triangle is:A = [s(s-a)(s-b)(s-c)]^1/2=[21(21-13)(21-14)(21-15)]^1/2

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:s= (a+b+c)/2 = (13 + 14 + 15)/2 = 21 cmWe know,The area of a triangle is:A = [s(s-a)(s-b)(s-c)]^1/2=[21(21-13)(21-14)(21-15)]^1/2=[21×8×7×6]^1/2

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:s= (a+b+c)/2 = (13 + 14 + 15)/2 = 21 cmWe know,The area of a triangle is:A = [s(s-a)(s-b)(s-c)]^1/2=[21(21-13)(21-14)(21-15)]^1/2=[21×8×7×6]^1/2=[7056]^1/2

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:s= (a+b+c)/2 = (13 + 14 + 15)/2 = 21 cmWe know,The area of a triangle is:A = [s(s-a)(s-b)(s-c)]^1/2=[21(21-13)(21-14)(21-15)]^1/2=[21×8×7×6]^1/2=[7056]^1/2=84 cm^2

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:s= (a+b+c)/2 = (13 + 14 + 15)/2 = 21 cmWe know,The area of a triangle is:A = [s(s-a)(s-b)(s-c)]^1/2=[21(21-13)(21-14)(21-15)]^1/2=[21×8×7×6]^1/2=[7056]^1/2=84 cm^2Now,

The given sides of the traingle are 13cm, 14cm and 15cm. Let a=13cm, b=14cm and c=15cm.So, semi-perimeter of the triangle is:s= (a+b+c)/2 = (13 + 14 + 15)/2 = 21 cmWe know,The area of a triangle is:A = [s(s-a)(s-b)(s-c)]^1/2=[21(21-13)(21-14)(21-15)]^1/2=[21×8×7×6]^1/2=[7056]^1/2=84 cm^2Now,The area of the triangle and parallelogram is same and both have same bas i.e. 14 cm.

The area of parallelogram is also:

The area of parallelogram is also:A=84 cm^2

The area of parallelogram is also:A=84 cm^2or, b×h=84 [As area of parallelogram = b×h]

The area of parallelogram is also:A=84 cm^2or, b×h=84 [As area of parallelogram = b×h]or, 14×h=84

The area of parallelogram is also:A=84 cm^2or, b×h=84 [As area of parallelogram = b×h]or, 14×h=84or,h = 84/14

The area of parallelogram is also:A=84 cm^2or, b×h=84 [As area of parallelogram = b×h]or, 14×h=84or,h = 84/14Hence, h = 6cm

The area of parallelogram is also:A=84 cm^2or, b×h=84 [As area of parallelogram = b×h]or, 14×h=84or,h = 84/14Hence, h = 6cmThus, the required height of the parallelogram is 6cm.